awk match substrで後方参照
awk ‘BEGIN{all=0} {if(/int([0-9]*)/){ match($1,/[0-9]+/); all+= substr($1,RSTART,RLENGTH); }} END{print all}’ < 201004.cnt
awk ‘BEGIN{all=0} {if(/int([0-9]*)/){ match($1,/[0-9]+/); all+= substr($1,RSTART,RLENGTH); }} END{print all}’ < 201004.cnt